By Sally Fahey
Aaron Nola gave up three homers in six innings, allowing five total runs in a no-decision against the Braves.
The Braves greeted Nola in the first inning with a two-run shot by Austin Riley.
Nola was up to the task in striking out the side after the first two men reached in the third and Ronald Acuna took third on a double steal, which kept things from totally spiraling out of control.
But Riley took him deep again so Nola left with a deficit — it was the first time all season Nola allowed multiple homers in a start.
He has a 4.59 ERA on a 1.12 WHIP after 11 starts. Nola’s scheduled to pitch against the Mets on Wednesday.